Mrrrr's Forum (VIEW ONLY)
Un forum care ofera solutii pentru unele probleme legate in general de PC. Pe langa solutii, aici puteti gasi si alte lucruri interesante // A forum that offers solutions to some PC related issues. Besides these, here you can find more interesting stuff.
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TRaP
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Inregistrat: acum 6 ani
Postari: 795
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Source:
Array formula:
=INDEX(Data;MODE(IF((Data<>"")*ISNA(MATCH(Data;$C$1:$C6;0));MATCH(Data;Data;0) * {1\1})))
Where Data is a named range which refers to:
=Sheet4!$A$1:INDEX(Sheet4!$A:$A; LOOKUP("zzz"; Sheet4!$A:$A; ROW(Sheet4!$A:$A)))
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Mrrrr
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 Inregistrat: acum 18 ani
Postari: 2247
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With use of a helper column for ranking
Helper column, assuming column S is the column for which ranking is made:
=IF(S6="";"";IF(COUNTIF(S$6:S6;S6)=COUNTIF($S$6:$S$100;S6);COUNTIF($S$6:$S$100;S6)+((1/ROW())/10);""))
The ranked strings from column S are obtained with this formula (dragged until it shows blank cells):
=IFERROR(INDEX($S$6:$S$19;MATCH(LARGE($T$6:$T$19;ROWS($1:1));$T$6:$T$19;0));"")
I'm using the helper column inside a table, so while the helper formula must remain the same even inside the table, the formula above could be:
=IFERROR(INDEX(Table2[Jud];MATCH(LARGE(Table2[Rnk];ROWS($1:1));Table2[Rnk];0));"")
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