Mrrrr's Forum (VIEW ONLY)
Un forum care ofera solutii pentru unele probleme legate in general de PC. Pe langa solutii, aici puteti gasi si alte lucruri interesante // A forum that offers solutions to some PC related issues. Besides these, here you can find more interesting stuff.
|
Nou pe simpatie:
Alexandra21
 | Femeie
24 ani
Calarasi
cauta Barbat
24 - 53 ani |
|
|
Mrrrr's Forum (VIEW ONLY)ReguliInregistrareLoginPozeNu sunteti logat. Lista Forumurilor Pe Tematici
|
| #1 |
TRaPModerator
Postari: 960
|
|
In a table in Column "Invoice date" I have dates inserted as text in the format DD.MM.YY.
I need an actual date to be able to filter the data. I don't want to modify the original date, just have another column with the correct date next to the raw data table.
=DATE(2000+RIGHT([@[Invoice date]];2); MID([@[Invoice date]];4;2); LEFT([@[Invoice date]];2))
Source:
ChatGPT
|
|
| |
|
| #2 |
TRaPModerator
Postari: 960
|
|
Encountered date in this format:
04.02.2026.
So with an ending dot.
Made this formula:
=LET(
rng; D28;
dot; RIGHT(rng;1)=".";
convert; IF(dot=TRUE;TEXTBEFORE(rng;".";3;0);rng);
datetext; TEXT(convert;"dd.mm.yyyy");
DATE(RIGHT(datetext;4); MID(datetext;4;2); LEFT(datetext;2))
) |
Of course, can use on entire range, or spill range:
=LET(
rng; CHOOSECOLS(A19#;1);
dot; RIGHT(rng;1)=".";
convert; IF(dot=TRUE;TEXTBEFORE(rng;".";3;0);rng);
datetext; TEXT(convert;"dd.mm.yyyy");
DATE(RIGHT(datetext;4); MID(datetext;4;2); LEFT(datetext;2))
) |
|
|
| |
|
